提交URL:http://demo.yqxbxb.com/f2019d/teach/formSubmit.php
演示地址:http://demo.yqxbxb.com/f2019d/teach/
支持三种提交方式
GET
POST
FILES
->select(DB::raw('sum(line_score) as score,student_id'))
->groupBy('student_id')
->get();
现在才注意,sum里面不能加引号,单引双引嵌套使用都不行,直接不加就OK了,或``这个是可以的
尽管拿去收藏不用谢
/**
* 数组、对象随机排序
* @param data
*/
randomArray(data){
let temp = [];
let len = data.length;
if(!len){
let kAll = Object.keys(data);
len = kAll.length;
for(let i = len;i>0;i--){
let num = Math.random();
num = Math.floor(num*i);
temp.push(data[kAll[num]]);
kAll.splice(num,1);
}
}else{
for(let i = len;i>0;i--){
let num = Math.random();
num = Math.floor(num*i);
temp.push(data[num]);
data.splice(num,1);
}
}
return temp;
}
UPDATE users as u2 SET u2.`password` = SELECT u.password as pwd FROM homestead.users as u LEFT JOIN homestead.teachers as t on u.id = t.user_id WHERE t.staff_no = '2003001415' LIMIT 1) WHERE u2.`loginname` = 'admin' LIMIT 1
这样会报错,是mysql本身不支持操作本身又把本身作为数据源(一眼看上去特别有真理,但是看看语句逻辑,在别的数据库是先查出数据,再更新数据,不矛盾呀,也许是mysql查询的时候有点懒,没把查询的结果做一个隔离,而是映射什么的)
解决办法:(包一层就解决了)
UPDATE users as u2 SET u2.`password` =
(SELECT pwd from (
SELECT u.password as pwd FROM homestead.users as u LEFT JOIN homestead.teachers as t on u.id = t.user_id WHERE t.staff_no = '2003001415' LIMIT 1) as uu)
WHERE u2.`loginname` = 'admin' LIMIT 1